Acquiring Signals in 2208B

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Anbarasan.10
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Acquiring Signals in 2208B

Post by Anbarasan.10 »

Hi,
I am using 2208B. I have to acquire and generate signal in 2208 B.I could able to acquire signals.I am using LabVIEW 2019.I have set over view buffer size as 2500000.For every iteration i am getting 2500000 samples.Time taken for one iteration is varying.It is approximately 125ms to 150 ms.I have fixed the sampling rate to 500MHz.How can i get manage the number of samples and time.For 2500000 samples loop iteration time should be 200 ms.Please help us to get rid of this problem.

AndrewA
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Re: Acquiring Signals in 2208B

Post by AndrewA »

When you say you set the 'overview buffer' that must mean you are running the streaming example?
You can set the streaming examples to capture continuously, with the autostop off.
Or are you using the block example? As 500MHz sampling is not possible in streaming mode? (2208B 9.6MS/s max in streaming mode)
2500000 samples x (1/500MHz) = 5ms capture time

The loop time in the software will vary due USB bus transfers and OS load etc. Also the rearm time of the scope trigger will vary.
So you would need to add code to time stamp the start and end of the capture and calculate a delay to get a constant time for each iteration of the loop.
Regards Andrew
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Anbarasan.10
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Re: Acquiring Signals in 2208B

Post by Anbarasan.10 »

Hi Andrew,
Thanks for your reply.My test duration is 10 sec.I want to capture entire 10 sec data at 500 MHz .Since my signal frequency is 1 MHz. I does not care about streaming display.Is there any way to capture data?.

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