If you go to the following folder (Windows7)

"C:\Users\{LoginName}\AppData\Local\Pico Technology\{long asciinumericstringname}

you will find a

"preferences.xml"

file which contains all the settings. If you copy this you will be able to restore settings if you accidentally delete them.

It's possible that the voltages from the current clamp are at a very low level, a different clamp that provides a higher voltage for a given current should provide a faster response.

It makes perfect sense to me so I have put in a feature request to enable serial decoding from a vertical cursor.

I have passed the information and traces on to the development team for investigation. While I am waiting for a definitive answer from then, and looking at the trace, I would suggest that it is not correctly locking onto the clock so can you try a few different timebases to see if it helps decode an...

If you downloaded the latest release candidate for Picoscope6, R6.6.37(RC), it includes the updated driver ps4000.dll it will appear in an sdk download soon.

You are correctly set up for clock polarity zero and phase of 1 by sampling clock on falling edge. I would suggest triggering on a digital channel, not Chan A, and looking at your data I would suggest rising edge on D1 with no pre trigger which will leave you with a clean trace before you start deco...

Can you try with a Collection Time of 200us/div so that you increase the sampling rate, and then repost the psdata file.

Drivers update

Drivers update

Can you post a psdata file showing the issue for us to take a look at. Go to "File->SaveCurrentWaveform" and save as .psdata

Thanks

Can you go to "File->SaveCurrentWaveform" to save a psdata file which you can post here for us to take a look at.

Which USB port are you connecting to on the PC end ?

And how much memory do you have on your PC ?

Can you please send this request to support@picotech.com

I have not seen your picture yet.

You have

using sum of the powers of the harmonics divided by the power of the fundamental

should it be

using sum of the powers of the harmonics divided by the power of the "fundamental plus the harmonics"